Check if a Bash array contains a value
This approach has the advantage of not needing to loop over all the elements (at least not explicitly). But since array_to_string_internal()
in array.c still loops over array elements and concatenates them into a string, it's probably not more efficient than the looping solutions proposed, but it's more readable.
if [[ " ${array[*]} " =~ " ${value} " ]]; then # whatever you want to do when array contains valuefiif [[ ! " ${array[*]} " =~ " ${value} " ]]; then # whatever you want to do when array doesn't contain valuefi
Note that in cases where the value you are searching for is one of the words in an array element with spaces, it will give false positives. For example
array=("Jack Brown")value="Jack"
The regex will see "Jack" as being in the array even though it isn't. So you'll have to change IFS
and the separator characters on your regex if you want still to use this solution, like this
IFS="|"array=("Jack Brown${IFS}Jack Smith")value="Jack"if [[ "${IFS}${array[*]}${IFS}" =~ "${IFS}${value}${IFS}" ]]; then echo "true"else echo "false"fiunset IFS # or set back to original IFS if previously set
This will print "false".
Obviously this can also be used as a test statement, allowing it to be expressed as a one-liner
[[ " ${array[*]} " =~ " ${value} " ]] && echo "true" || echo "false"
Below is a small function for achieving this. The search string is the first argument and the rest are the array elements:
containsElement () { local e match="$1" shift for e; do [[ "$e" == "$match" ]] && return 0; done return 1}
A test run of that function could look like:
$ array=("something to search for" "a string" "test2000")$ containsElement "a string" "${array[@]}"$ echo $?0$ containsElement "blaha" "${array[@]}"$ echo $?1
One-line solution
printf '%s\n' "${myarray[@]}" | grep -P '^mypattern$'
Explanation
The printf
statement prints each element of the array on a separate line.
The grep
statement uses the special characters ^
and $
to find a line that contains exactly the pattern given as mypattern
(no more, no less).
Usage
To put this into an if ... then
statement:
if printf '%s\n' "${myarray[@]}" | grep -q -P '^mypattern$'; then # ...fi
I added a -q
flag to the grep
expression so that it won't print matches; it will just treat the existence of a match as "true."