Print array elements on separate lines in Bash?
Try doing this :
$ printf '%s\n' "${my_array[@]}"
The difference between $@
and $*
:
Unquoted, the results are unspecified. In Bash, both expand to separate argsand then wordsplit and globbed.
Quoted,
"$@"
expands each element as a separate argument, while"$*"
expands to the args merged into one argument:"$1c$2c..."
(wherec
isthe first char ofIFS
).
You almost always want "$@"
. Same goes for "${arr[@]}"
.
Always quote them!
Using for:
for each in "${alpha[@]}"do echo "$each"done
Using history; note this will fail if your values contain !
:
history -p "${alpha[@]}"
Using basename; note this will fail if your values contain /
:
basename -a "${alpha[@]}"
Using shuf; note that results might not come out in order:
shuf -e "${alpha[@]}"