Django Admin: How to display value of fields with list_display from two models which are in oneToOne relation?

Finally!!! I solved it. As I thought it was simple, but I had to do it other way around and with multi table inheritance:

models.pyclass Member(models.Model):    ID = models.AutoField(primary_key=True)    FIRST_NAME = models.CharField('First name', max_length=50)    LAST_NAME = models.CharField('Last name', max_length=50)# Using multi table inheritance - automaticly creates one to one fieldclass MemberDetail(Member):    DATE_OF_BIRTH = models.DateField('Date of birth')    EMAIL = models.EmailField('E-mail')    PHONE = models.CharField('Phone', max_length=15)

Now for admin.py

admin.pyclass MemberDetailAdmin(admin.ModelAdmin):    list_display = ("FIRST_NAME", "LAST_NAME", "DATE_OF_BIRTH", "EMAIL", "PHONE")admin.site.register(MemberDetail, MemberDetailAdmin)

That's it. Maybe, there is other solutions, but this is good for me.

In case anyone stumbles into this question/problem, I don't know a direct way to access fields from a OneToOne relationship, however, I was able to fix the problem with the following snippet. Notice that I CAN access OneToOne fields in list_filter by using two '_' to access fields of an OneToOne, for example: modelB_fieldOne.

@admin.display(description='Date')    def transaction_date(self, purchase):        return purchase.transaction.datelist_display = ('product', 'transaction_date')list_filter = ('product', 'transaction__date')

You should just be able to do 'member_detail__email', etc. in list_display

Since it's a 1-1 you should have a backref, and associated fields are referenced using two underscores.