Is Chrome's JavaScript console lazy about evaluating arrays? Is Chrome's JavaScript console lazy about evaluating arrays? google-chrome google-chrome

Is Chrome's JavaScript console lazy about evaluating arrays?


Thanks for the comment, tec. I was able to find an existing unconfirmed Webkit bug that explains this issue: https://bugs.webkit.org/show_bug.cgi?id=35801 (EDIT: now fixed!)

There appears to be some debate regarding just how much of a bug it is and whether it's fixable. It does seem like bad behavior to me. It was especially troubling to me because, in Chrome at least, it occurs when the code resides in scripts that are executed immediately (before the page is loaded), even when the console is open, whenever the page is refreshed. Calling console.log when the console is not yet active only results in a reference to the object being queued, not the output the console will contain. Therefore, the array (or any object), will not be evaluated until the console is ready. It really is a case of lazy evaluation.

However, there is a simple way to avoid this in your code:

var s = ["hi"];console.log(s.toString());s[0] = "bye";console.log(s.toString());

By calling toString, you create a representation in memory that will not be altered by following statements, which the console will read when it is ready. The console output is slightly different from passing the object directly, but it seems acceptable:

hibye


From Eric's explanation, it is due to console.log() being queued up, and it prints a later value of the array (or object).

There can be 5 solutions:

1. arr.toString()   // not well for [1,[2,3]] as it shows 1,2,32. arr.join()       // same as above3. arr.slice(0)     // a new array is created, but if arr is [1, 2, arr2, 3]                     //   and arr2 changes, then later value might be shown4. arr.concat()     // a new array is created, but same issue as slice(0)5. JSON.stringify(arr)  // works well as it takes a snapshot of the whole array                         //   or object, and the format shows the exact structure


You can clone an array with Array#slice:

console.log(s); // ["bye"], i.e. incorrectconsole.log(s.slice()); // ["hi"], i.e. correct

A function that you can use instead of console.log that doesn't have this problem is as follows:

console.logShallowCopy = function () {    function slicedIfArray(arg) {        return Array.isArray(arg) ? arg.slice() : arg;    }    var argsSnapshot = Array.prototype.map.call(arguments, slicedIfArray);    return console.log.apply(console, argsSnapshot);};

For the case of objects, unfortunately, the best method appears to be to debug first with a non-WebKit browser, or to write a complicated function to clone. If you are only working with simple objects, where order of keys doesn't matter and there are no functions, you could always do:

console.logSanitizedCopy = function () {    var args = Array.prototype.slice.call(arguments);    var sanitizedArgs = JSON.parse(JSON.stringify(args));    return console.log.apply(console, sanitizedArgs);};

All of these methods are obviously very slow, so even more so than with normal console.logs, you have to strip them off after you're done debugging.