Different object size of True and False in Python 3

It is because bool is a subclass of int in both Python 2 and 3.

>>> issubclass(bool, int)True

But the int implementation has changed.

In Python 2, int was the one that was 32 or 64 bits, depending on the system, as opposed to arbitrary-length long.

In Python 3, int is arbitrary-length - the long of Python 2 was renamed to int and the original Python 2 int dropped altogether.

In Python 2 you get the exactly same behaviour for long objects 1L and 0L:

Python 2.7.15rc1 (default, Apr 15 2018, 21:51:34) [GCC 7.3.0] on linux2Type "help", "copyright", "credits" or "license" for more information.>>> import sys>>> sys.getsizeof(1L)28>>> sys.getsizeof(0L)24

The long/Python 3 int is a variable-length object, just like a tuple - when it is allocated, enough memory is allocated to hold all the binary digits required to represent it. The length of the variable part is stored in the object head. 0 requires no binary digits (its variable length is 0), but even 1 spills over, and requires extra digits.

I.e. 0 is represented as binary string of length 0:

<>

and 1 is represented as a 30-bit binary string:

<000000000000000000000000000001>

The default configuration in Python uses 30 bits in a uint32_t; so 2**30 - 1 still fits in 28 bytes on x86-64, and 2**30 will require 32;

2**30 - 1 will be presented as

<111111111111111111111111111111>

i.e. all 30 value bits set to 1; 2**30 will need more, and it will have internal representation

<000000000000000000000000000001000000000000000000000000000000>

As for True using 28 bytes instead of 24 - you need not worry. True is a singleton and therefore only 4 bytes are lost in total in any Python program, not 4 for every usage of True.

Both True and False are longobjects in CPython:

struct _longobject _Py_FalseStruct = {    PyVarObject_HEAD_INIT(&PyBool_Type, 0)    { 0 }};struct _longobject _Py_TrueStruct = {    PyVarObject_HEAD_INIT(&PyBool_Type, 1)    { 1 }};

You thus can say that a Boolean is a subclass of a python-3.x int where True takes as value 1, and False takes as value 0. We thus make a call to PyVarObject_HEAD_INIT with as type parameter a reference to PyBool_Type and with ob_size as value 0 and 1 respectively.

Now since python-3.x, there is no long anymore: these have been merged, and the int object will, depending on the size of the number, take a different value.

If we inspect the source code of the longlobject type, we see:

/* Long integer representation.   The absolute value of a number is equal to        SUM(for i=0 through abs(ob_size)-1) ob_digit[i] * 2**(SHIFT*i)   Negative numbers are represented with ob_size < 0;   zero is represented by ob_size == 0.   In a normalized number, ob_digit[abs(ob_size)-1] (the most significant   digit) is never zero. Also, in all cases, for all valid i,        0 <= ob_digit[i] <= MASK.   The allocation function takes care of allocating extra memory   so that ob_digit[0] ... ob_digit[abs(ob_size)-1] are actually available.   CAUTION: Generic code manipulating subtypes of PyVarObject has to   aware that ints abuse ob_size's sign bit.*/struct _longobject {    PyObject_VAR_HEAD    digit ob_digit[1];};

To make a long story short, an _longobject can be seen as an array of "digits", but you should here see digits not as decimal digits, but as groups of bits that thus can be added, multiplied, etc.

Now as is specified in the comment, it says that:

   zero is represented by ob_size == 0.

So in case the value is zero, no digits are added, whereas for small integers (values less than 2³⁰ in CPython), it takes one digit, and so on.

In python-2.x, there were two types of representations for numbers, ints (with a fixed size), you could see this as "one digit", and longs, with multiple digits. Since a bool was a subclass of int, both True and False occupied the same space.

I haven't seen CPython code for this, but I believe this has something to do with optimization of integers in Python 3. Probably, as long was dropped, some optimizations were unified. int in Python 3 is arbitrary-sized int – the same as long was in Python 2. As bool stores in the same way as new int, it affects both.

Interesting part:

>>> (0).__sizeof__()24>>> (1).__sizeof__()  # Here one more "block" is allocated28>>> (2**30-1).__sizeof__()  # This is the maximum integer size fitting into 2828

+ bytes for object headers should complete the equation.