Python 3 turn range to a list

You can just construct a list from the range object:

my_list = list(range(1, 1001))

This is how you do it with generators in python2.x as well. Typically speaking, you probably don't need a list though since you can come by the value of my_list[i] more efficiently (i + 1), and if you just need to iterate over it, you can just fall back on range.

Also note that on python2.x, xrange is still indexable¹. This means that range on python3.x also has the same property²

^{1print xrange(30)[12] works for python2.x}

^{2The analogous statement to 1 in python3.x is print(range(30)[12]) and that works also.}

In Pythons <= 3.4 you can, as others suggested, use list(range(10)) in order to make a list out of a range (In general, any iterable).

Another alternative, introduced in Python 3.5 with its unpacking generalizations, is by using * in a list literal []:

>>> r = range(10)>>> l = [*r]>>> print(l)[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

Though this is equivalent to list(r), it's literal syntax and the fact that no function call is involved does let it execute faster. It's also less characters, if you need to code golf :-)

in Python 3.x, the range() function got its own type. so in this case you must use iterator

list(range(1000))