python encode()

No, using encode() to hexlify isn't nice.

The way you use the hex codec worked in Python 2 because you can call encode() on 8-bit strings in Python 2, ie you can encode something that is already encoded. That doesn't make sense. encode() is for encoding Unicode strings into 8-bit strings, not for encoding 8-bit strings as 8-bit strings.

In Python 3 you can't call encode() on 8-bit strings anymore, so the hex codec became pointless and was removed.

Although you theoretically could have a hex codec and use it like this:

>>> import codecs>>> hexlify = codecs.getencoder('hex')>>> hexlify(b'Blaah')[0]b'426c616168'

Using binascii is easier and nicer:

>>> import binascii>>> binascii.hexlify(b'Blaah')b'426c616168'

this is the same answer for the above but i modified it so it works with python 3.

import binasciifrom Crypto.Cipher import AESfrom Crypto import Randomdef encrypt(passwrd, message):    msglist = []    key = bytes(passwrd, "utf-8")    iv = Random.new().read(AES.block_size)    cipher = AES.new(key, AES.MODE_CFB, iv)    msg = iv + cipher.encrypt(bytes(message, "utf-8"))    msg = binascii.hexlify(msg)    for letter in str(msg):        msglist.append(letter)    msglist.remove("b")    msglist.remove("'")    msglist.remove("'")    for letter in msglist:        print(letter, end="")    print("")def decrypt(passwrd, message):    msglist = []    key = bytes(passwrd, "utf-8")    iv = Random.new().read(AES.block_size)    cipher = AES.new(key, AES.MODE_CFB, iv)    msg = cipher.decrypt(binascii.unhexlify(bytes(message, "utf-8")))[len(iv):]    for letter in str(msg):        msglist.append(letter)    msglist.remove("b")    msglist.remove("'")    msglist.remove("'")    for letter in msglist:        print(letter, end="")    print("")