Extracting an attribute value with beautifulsoup Extracting an attribute value with beautifulsoup python python

Extracting an attribute value with beautifulsoup

.find_all() returns list of all found elements, so:

input_tag = soup.find_all(attrs={"name" : "stainfo"})

input_tag is a list (probably containing only one element). Depending on what you want exactly you either should do:

output = input_tag[0]['value']

or use .find() method which returns only one (first) found element:

input_tag = soup.find(attrs={"name": "stainfo"})output = input_tag['value']

In Python 3.x, simply use get(attr_name) on your tag object that you get using find_all:

xmlData = Nonewith open('conf//test1.xml', 'r') as xmlFile:    xmlData = xmlFile.read()xmlDecoded = xmlDataxmlSoup = BeautifulSoup(xmlData, 'html.parser')repElemList = xmlSoup.find_all('repeatingelement')for repElem in repElemList:    print("Processing repElem...")    repElemID = repElem.get('id')    repElemName = repElem.get('name')    print("Attribute id = %s" % repElemID)    print("Attribute name = %s" % repElemName)

against XML file conf//test1.xml that looks like:

<?xml version="1.0" encoding="UTF-8" standalone="yes"?><root>    <singleElement>        <subElementX>XYZ</subElementX>    </singleElement>    <repeatingElement id="11" name="Joe"/>    <repeatingElement id="12" name="Mary"/></root>


Processing repElem...Attribute id = 11Attribute name = JoeProcessing repElem...Attribute id = 12Attribute name = Mary

If you want to retrieve multiple values of attributes from the source above, you can use findAll and a list comprehension to get everything you need:

import urllibf = urllib.urlopen("")s = f.read()f.close()from BeautifulSoup import BeautifulStoneSoupsoup = BeautifulStoneSoup(s)inputTags = soup.findAll(attrs={"name" : "stainfo"})### You may be able to do findAll("input", attrs={"name" : "stainfo"})output = [x["stainfo"] for x in inputTags]print output### This will print a list of the values.