Fastest way to get the first object from a queryset in django? Fastest way to get the first object from a queryset in django? python python

Fastest way to get the first object from a queryset in django?


Use the convenience methods .first() and .last():

MyModel.objects.filter(blah=blah).first()

They both swallow the resulting exception and return None if the queryset returns no objects.

These were added in Django 1.6, which was released in Nov 2013.


You can use array slicing:

Entry.objects.all()[:1].get()

Which can be used with .filter():

Entry.objects.filter()[:1].get()

You wouldn't want to first turn it into a list because that would force a full database call of all the records. Just do the above and it will only pull the first. You could even use .order_by() to ensure you get the first you want.

Be sure to add the .get() or else you will get a QuerySet back and not an object.


r = list(qs[:1])if r:  return r[0]return None


matomo