Get human readable version of file size? Get human readable version of file size? python python

Get human readable version of file size?

Addressing the above "too small a task to require a library" issue by a straightforward implementation (using f-strings, so Python 3.6+):

def sizeof_fmt(num, suffix="B"):    for unit in ["", "Ki", "Mi", "Gi", "Ti", "Pi", "Ei", "Zi"]:        if abs(num) < 1024.0:            return f"{num:3.1f}{unit}{suffix}"        num /= 1024.0    return f"{num:.1f}Yi{suffix}"


  • all currently known binary prefixes
  • negative and positive numbers
  • numbers larger than 1000 Yobibytes
  • arbitrary units (maybe you like to count in Gibibits!)


>>> sizeof_fmt(168963795964)'157.4GiB'

by Fred Cirera

A library that has all the functionality that it seems you're looking for is humanize. humanize.naturalsize() seems to do everything you're looking for.

The following works in Python 3.6+, is, in my opinion, the easiest to understand answer on here, and lets you customize the amount of decimal places used.

def human_readable_size(size, decimal_places=2):    for unit in ['B', 'KiB', 'MiB', 'GiB', 'TiB', 'PiB']:        if size < 1024.0 or unit == 'PiB':            break        size /= 1024.0    return f"{size:.{decimal_places}f} {unit}"