How to find recursively for a tag of XML using LXML?

You can use XPath to search recursively:

>>> from lxml import etree>>> q = etree.fromstring('<xml><hello>a</hello><x><hello>b</hello></x></xml>')>>> q.findall('hello')     # Tag name, first level only.[<Element hello at 414a7c8>]>>> q.findall('.//hello')  # XPath, recursive.[<Element hello at 414a7c8>, <Element hello at 414a818>]

iterfind() iterates over all Elements that match the path expression

findall() returns a list of matching Elements

find() efficiently returns only the first match

findtext() returns the .text content of the first match

Illustrative Examples:

>>> root = etree.XML("<root><a x='123'>aText<b/><c/><b/></a></root>")#Find a child of an Element:>>> print(root.find("b"))None>>> print(root.find("a").tag)a#Find an Element anywhere in the tree:>>> print(root.find(".//b").tag)b>>> [ b.tag for b in root.iterfind(".//b") ]['b', 'b']#Find Elements with a certain attribute:>>> print(root.findall(".//a[@x]")[0].tag)a>>> print(root.findall(".//a[@y]"))[]

Reference:http://lxml.de/tutorial.html#elementpath

(This answer is relevant selective selection from the content at this link)