How to initialize a two-dimensional array in Python?
A pattern that often came up in Python was
bar = []for item in some_iterable: bar.append(SOME EXPRESSION)
which helped motivate the introduction of list comprehensions, which convert that snippet to
bar = [SOME EXPRESSION for item in some_iterable]
which is shorter and sometimes clearer. Usually you get in the habit of recognizing these and often replacing loops with comprehensions.
Your code follows this pattern twice
twod_list = [] \ for i in range (0, 10): \ new = [] \ can be replaced } this too for j in range (0, 10): } with a list / new.append(foo) / comprehension / twod_list.append(new) /
Don't use [[v]*n]*n
, it is a trap!
>>> a = [[0]*3]*3>>> a[[0, 0, 0], [0, 0, 0], [0, 0, 0]]>>> a[0][0]=1>>> a[[1, 0, 0], [1, 0, 0], [1, 0, 0]]
but
t = [ [0]*3 for i in range(3)]
works great.
You can use a list comprehension:
x = [[foo for i in range(10)] for j in range(10)]# x is now a 10x10 array of 'foo' (which can depend on i and j if you want)