How would I get everything before a : in a string Python How would I get everything before a : in a string Python python python

How would I get everything before a : in a string Python


Just use the split function. It returns a list, so you can keep the first element:

>>> s1.split(':')['Username', ' How are you today?']>>> s1.split(':')[0]'Username'


Using index:

>>> string = "Username: How are you today?">>> string[:string.index(":")]'Username'

The index will give you the position of : in string, then you can slice it.

If you want to use regex:

>>> import re>>> re.match("(.*?):",string).group()'Username'                       

match matches from the start of the string.

you can also use itertools.takewhile

>>> import itertools>>> "".join(itertools.takewhile(lambda x: x!=":", string))'Username'


You don't need regex for this

>>> s = "Username: How are you today?"

You can use the split method to split the string on the ':' character

>>> s.split(':')['Username', ' How are you today?']

And slice out element [0] to get the first part of the string

>>> s.split(':')[0]'Username'


matomo