print python stack trace without exception being raised
>>> def f():... def g():... traceback.print_stack()... g()...>>> f() File "<stdin>", line 1, in <module> File "<stdin>", line 4, in f File "<stdin>", line 3, in g
Edit: You can also use extract_stack, take a slice (e.g. stack[5:]
for exclude the first 5 levels) and use format_list to get a print-ready stacktrace ('\n'.join(traceback.format_list(...))
)
Instead of printing to stdout, if you need a string to pass to a logger you can use:
''.join(traceback.format_stack())
Note, that traceback.format_stack() returns the stacktrace as a formatted list of strings, so you can slice it anyway you want. To get the last few elements of the stacktrace you could do:
''.join(traceback.format_stack()[-N:])
Where N is the number of levels you are interested in.