Python argparse ignore unrecognised arguments Python argparse ignore unrecognised arguments python python

Python argparse ignore unrecognised arguments


args = parser.parse_args()


args, unknown = parser.parse_known_args()

For example,

import argparseparser = argparse.ArgumentParser()parser.add_argument('--foo')args, unknown = parser.parse_known_args(['--foo', 'BAR', 'spam'])print(args)# Namespace(foo='BAR')print(unknown)# ['spam']

You can puts the remaining parts into a new argument with parser.add_argument('args', nargs=argparse.REMAINDER) if you want to use them.

Actually argparse does still "ignore" _unrecognized_args. As long as these "unrecognized" arguments don't use the default prefix you will hear no complaints from the parser.

Using @anutbu's configuration but with the standard parse.parse_args(), if we were to execute our program with the following arguments.

$ program --foo BAR a b +cd e

We will have this Namespaced data collection to work with.

Namespace(_unrecognized_args=['a', 'b', '+cd', 'e'], foo='BAR')

If we wanted the default prefix - ignored we could change the ArgumentParser and decide we are going to use a + for our "recognized" arguments instead.

parser = argparse.ArgumentParser(prefix_chars='+')parser.add_argument('+cd')

The same command will produce

Namespace(_unrecognized_args=['--foo', 'BAR', 'a', 'b'], cd='e')

Put that in your pipe and smoke it =)