Reading integers from binary file in Python

The read method returns a sequence of bytes as a string. To convert from a string byte-sequence to binary data, use the built-in struct module: http://docs.python.org/library/struct.html.

import structprint(struct.unpack('i', fin.read(4)))

Note that unpack always returns a tuple, so struct.unpack('i', fin.read(4))[0] gives the integer value that you are after.

You should probably use the format string '<i' (< is a modifier that indicates little-endian byte-order and standard size and alignment - the default is to use the platform's byte ordering, size and alignment). According to the BMP format spec, the bytes should be written in Intel/little-endian byte order.

An alternative method which does not make use of 'struct.unpack()' would be to use NumPy:

import numpy as npf = open("file.bin", "r")a = np.fromfile(f, dtype=np.uint32)

'dtype' represents the datatype and can be int#, uint#, float#, complex# or a user defined type. See numpy.fromfile.

Personally prefer using NumPy to work with array/matrix data as it is a lot faster than using Python lists.

As of Python 3.2+, you can also accomplish this using the from_bytes native int method:

file_size = int.from_bytes(fin.read(2), byteorder='big')

Note that this function requires you to specify whether the number is encoded in big- or little-endian format, so you will have to determine the endian-ness to make sure it works correctly.