Search for "does-not-contain" on a DataFrame in pandas

You can use the invert (~) operator (which acts like a not for boolean data):

new_df = df[~df["col"].str.contains(word)]

, where new_df is the copy returned by RHS.

contains also accepts a regular expression...

If the above throws a ValueError, the reason is likely because you have mixed datatypes, so use na=False:

new_df = df[~df["col"].str.contains(word, na=False)]

Or,

new_df = df[df["col"].str.contains(word) == False]

python pandas contains

I was having trouble with the not (~) symbol as well, so here's another way from another StackOverflow thread:

df[df["col"].str.contains('this|that')==False]

python pandas contains

You can use Apply and Lambda :

df[df["col"].apply(lambda x: word not in x)]

Or if you want to define more complex rule, you can use AND:

df[df["col"].apply(lambda x: word_1 not in x and word_2 not in x)]

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