super() fails with error: TypeError "argument 1 must be type, not classobj" when parent does not inherit from object
Your problem is that class B is not declared as a "new-style" class. Change it like so:
class B(object):
and it will work.
super()
and all subclass/superclass stuff only works with new-style classes. I recommend you get in the habit of always typing that (object)
on any class definition to make sure it is a new-style class.
Old-style classes (also known as "classic" classes) are always of type classobj
; new-style classes are of type type
. This is why you got the error message you saw:
TypeError: super() argument 1 must be type, not classobj
Try this to see for yourself:
class OldStyle: passclass NewStyle(object): passprint type(OldStyle) # prints: <type 'classobj'>print type(NewStyle) # prints <type 'type'>
Note that in Python 3.x, all classes are new-style. You can still use the syntax from the old-style classes but you get a new-style class. So, in Python 3.x you won't have this problem.
Also, if you can't change class B, you can fix the error by using multiple inheritance.
class B: def meth(self, arg): print argclass C(B, object): def meth(self, arg): super(C, self).meth(arg)print C().meth(1)
If the python version is 3.X, it's okay.
I think your python version is 2.X, the super would work when adding this code
__metaclass__ = type
so the code is
__metaclass__ = typeclass B: def meth(self, arg): print argclass C(B): def meth(self, arg): super(C, self).meth(arg)print C().meth(1)