FizzBuzz using ternary conditional operator

Some parentheses might help:

puts (i%3 == 0) ? ((i%5 == 0) ? "FizzBuzz" : "Buzz") : ((i%5 == 0) ? "Fizz" : i)

So, if i is divisible by 3, then it checks whether i is also divisible by 5. If so, it prints "FizzBuzz" otherwise just "Buzz". If i is not divisible by three, then it checks divisibility by 5 again and prints "Fizz" if so, otherwise just i.

Here is a description of the FizzBuzz problem as stated in this Jeff Atwood article.

Write a program that prints the numbers from 1 to 100. But for multiples of three print "Fizz" instead of the number and for the multiples of five print "Buzz". For numbers which are multiples of both three and five print "FizzBuzz".

A ternary operator is shorthand writing for an if-else statement. The general format is:

cond ? evaluate_if_cond_is_true : evaluate_if_cond_is_false

So if I write:

int isEven = (i % 2 == 0) ? 1 : 0;

Is equivalent to the following code:

if (i % 2 == 0) {    isEven = 1;} else {    isEven = 0;}

Where cond is i % 2 == 0, evaluate_if_cond_is_true is 1 and evaluate_if_cond_is_false is 0.

The nice thing about ternary operators is that they can be combined. This means that the statement to execute when either condition evaluates to true or false can be another ternary operator.

Let put the entire condition in a more readable fashion:

i%3==0 ?    i%5==0 ?        "FizzBuzz"        : "Buzz"    : i%5==0 ?        "Fizz"        : i

And mapping this to if-else statements is easy with the rules explained above:

if (i%3==0) {    if (i%5==0) {        "FizzBuzz"    } else {        "Buzz"    }} else {    if (i%5==0) {        "Fizz"    } else {        i    }}

This is not valid code but because the result of the ternary operator is inlined in the result expression it is used as input for the puts command.

For fun, here's another way:

puts (1..100).map {|i| (fb = [["Fizz"][i%3],["Buzz"][i%5]].compact.join).empty? ? i : fb}

And another:

(1..100).zip([nil,nil,"Fizz"]*34,[nil,nil,nil,nil,"Buzz"]*20).map {|a,b,c| b || c ? [b,c].join : a}