Why Use Integer Instead of Long? Why Use Integer Instead of Long? vba vba

Why Use Integer Instead of Long?

Integer variables are stored as 16-bit (2-byte) numbers

Office VBA Reference

Long (long integer) variables are stored as signed 32-bit (4-byte) numbers

Office VBA Reference

So, the benefit is in reduced memory space. An Integer takes up half the memory that a Long does. Now, we are talking about 2 bytes, so it's not going to make a real difference for individual integers, it's only a concern when you are dealing with TONS of integers (e.g large arrays) and memory usage is critical.

BUT on a 32 bit system, the halved memory usage comes at a performance cost. When the processor actually performs some computation with a 16 bit integer (e.g. incrementing a loop counter), the value silently gets converted to a temporary Long without the benefit of the larger range of numbers to work with. Overflows still happen, and the register that the processor uses to store the values for the calculation will take the same amount of memory (32 bits) either way. Performance may even be hurt because the datatype has to be converted (at a very low level).

Not the reference I was looking for but....

My understanding is that the underlying VB engine converts integers to long even if its declared as an integer. Therefore a slight speed decrease can be noted. I have believed this for some time and perhaps thats also why the above statement was made, I didnt ask for reasoning.

ozgrid forums

This is the reference I was looking for.

Short answer, in 32-bit systems 2 byte integers are converted to 4 byte Longs. There really is no other way so that respective bits correctly line up for any form of processing. Consider the following

MsgBox Hex(-1) = Hex(65535) ' = True

Obviously -1 does not equal 65535 yet the computer is returning the correct answer, namely "FFFF" = "FFFF"

However had we coerced the -1 to a long first we would have got the right answer (the 65535 being greater than 32k is automatically a long)

MsgBox Hex(-1&) = Hex(65535) ' = False


Generally there is no point in VBA to declare "As Integer" in modern systems, except perhaps for some legacy API's that expect to receive an Integer.

pcreview forum

And at long last I found the msdn documentation I was really truly looking for.

Traditionally, VBA programmers have used integers to hold small numbers, because they required less memory. In recent versions, however, VBA converts all integer values to type Long, even if they're declared as type Integer. So there's no longer a performance advantage to using Integer variables; in fact, Long variables may be slightly faster because VBA does not have to convert them.

To clarify based on the comments: Integers still require less memory to store - a large array of integers will need significantly less RAM than an Long array with the same dimensions. But because the processor needs to work with 32 bit chunks of memory, VBA converts Integers to Longs temporarily when it performs calculations

So, in summary, there's almost no good reason to use an Integer type these days. Unless you need to Interop with an old API call that expects a 16 bit int, or you are working with large arrays of small integers and memory is at a premium.

One thing worth pointing out is that some old API functions may be expecting parameters that are 16-bit (2-byte) Integers and if you are on a 32 bit and trying to pass an Integer (that is already a 4-byte long) by reference it will not work due to difference in length of bytes.

Thanks to Vba4All for pointing that out.

As noted in other answers, the real difference between int and long is the size of its memory space and therefore the size of the number it can hold.

here is the full documentation on these datatypeshttp://msdn.microsoft.com/en-us/library/office/ms474284(v=office.14).aspx

an Integer is 16 bits and can represent a value between -32,768 and 32,767

a Long is 32 bits and can represent -2,147,483,648 to 2,147,483,647

and there is a LongLong which is 64 bits and can handle like 9 pentilion

One of the most important things to remember on this is that datatypes differ by both language and operating system / platform. In your world of VBA a long is 32 bits, but in c# on a 64 bit processor a long is 64 bits. This can introduce significant confusion.

Although VBA does not have support for it, when you move to any other language in .net or java or other, I much prefer to use the system datatypes of int16, int32 and int64 which allows me to b much more transparent about the values that can be held in these datatypes.

Even though this post is four years old, I was curious about this and ran some tests. The most important thing to note is that a coder should ALWAYS declare a variable as SOMETHING. Undeclared variables clearly performed the worst (undeclared are technically Variant)

Long did perform the fastest, so I have to think that Microsoft's recommendation to always use Long instead of Integer makes sense. I'm guessing the same as true with Byte, but most coders don't use this.


Variable Olympics

Code Used:

Sub VariableOlymics()'Run this macro as many times as you'd like, with an activesheet ready for data'in cells B2 to D6Dim beginTIME As Double, trials As Long, i As Long, p As Long    trials = 1000000000    p = 0    beginTIME = Now    For i = 1 To trials        Call boomBYTE    Next i    Call Finished(p, Now - beginTIME, CDbl(trials))    p = p + 1    beginTIME = Now    For i = 1 To trials        Call boomINTEGER    Next i    Call Finished(p, Now - beginTIME, CDbl(trials))    p = p + 1    beginTIME = Now    For i = 1 To trials        Call boomLONG    Next i    Call Finished(p, Now - beginTIME, CDbl(trials))    p = p + 1    beginTIME = Now    For i = 1 To trials        Call boomDOUBLE    Next i    Call Finished(p, Now - beginTIME, CDbl(trials))    p = p + 1    beginTIME = Now    For i = 1 To trials        Call boomUNDECLARED    Next i    Call Finished(p, Now - beginTIME, CDbl(trials))    p = p + 1End SubPrivate Sub boomBYTE()Dim a As Byte, b As Byte, c As Byte    a = 1    b = 1 + a    c = 1 + b    c = c + 1End SubPrivate Sub boomINTEGER()Dim a As Integer, b As Integer, c As Integer    a = 1    b = 1 + a    c = 1 + b    c = c + 1End SubPrivate Sub boomLONG()Dim a As Long, b As Long, c As Long    a = 1    b = 1 + a    c = 1 + b    c = c + 1End SubPrivate Sub boomDOUBLE()Dim a As Double, b As Double, c As Double    a = 1    b = 1 + a    c = 1 + b    c = c + 1End SubPrivate Sub boomUNDECLARED()    a = 1    b = 1 + a    c = 1 + b    c = c + 1End SubPrivate Sub Finished(i As Long, timeUSED As Double, trials As Double)    With Range("B2").Offset(i, 0)            .Value = .Value + trials            .Offset(0, 1).Value = .Offset(0, 1).Value + timeUSED            .Offset(0, 2).FormulaR1C1 = "=ROUND(RC[-1]*3600*24,0)"    End WithEnd Sub