Parse XML with namespaces in Java using xpath Parse XML with namespaces in Java using xpath xml xml

Parse XML with namespaces in Java using xpath


You need to set a NamespaceContext on the XPath:

Demo

package forum11644994;import java.io.StringReader;import java.util.Iterator;import javax.xml.namespace.NamespaceContext;import javax.xml.parsers.*;import javax.xml.xpath.*;import org.w3c.dom.Document;import org.w3c.dom.NodeList;import org.xml.sax.InputSource;public class Demo {    public static void main(String[] args) throws Exception {        String xml = "<soapenv:Envelope xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" xmlns:soapenv=\"http://schemas.xmlsoap.org/soap/envelope/\" xmlns:ser=\"http://services.web.post.list.com\"><soapenv:Header><authInfo xsi:type=\"soap:authentication\" xmlns:soap=\"http://list.com/services/SoapRequestProcessor\"><!--You may enter the following 2 items in any order--><username xsi:type=\"xsd:string\">dfasf@google.com</username><password xsi:type=\"xsd:string\">PfasdfRem91</password></authInfo></soapenv:Header></soapenv:Envelope>";        System.out.println(xml);        DocumentBuilderFactory domFactory = DocumentBuilderFactory                .newInstance();        domFactory.setNamespaceAware(true);        DocumentBuilder builder = domFactory.newDocumentBuilder();        Document doc = builder.parse(new InputSource(new StringReader(xml)));        XPath xpath = XPathFactory.newInstance().newXPath();        xpath.setNamespaceContext(new NamespaceContext() {            @Override            public Iterator getPrefixes(String arg0) {                return null;            }            @Override            public String getPrefix(String arg0) {                return null;            }            @Override            public String getNamespaceURI(String arg0) {                if("soapenv".equals(arg0)) {                    return "http://schemas.xmlsoap.org/soap/envelope/";                }                return null;            }        });        // XPath Query for showing all nodes value        try {            XPathExpression expr = xpath                    .compile("/soapenv:Envelope/soapenv:Header/authInfo/password");            Object result = expr.evaluate(doc, XPathConstants.NODESET);            NodeList nodes = (NodeList) result;            System.out.println("Got " + nodes.getLength() + " nodes");            // System.out.println(nodes.item(0).getNodeValue());        } catch (Exception E) {            System.out.println(E);        }    }}

Output

<soapenv:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:ser="http://services.web.post.list.com"><soapenv:Header><authInfo xsi:type="soap:authentication" xmlns:soap="http://list.com/services/SoapRequestProcessor"><!--You may enter the following 2 items in any order--><username xsi:type="xsd:string">dfasf@google.com</username><password xsi:type="xsd:string">PfasdfRem91</password></authInfo></soapenv:Header></soapenv:Envelope>Got 1 nodes


Adding some more to the latest reply..To get the particular node value you can use the below--[System.out.println(nodes.item(0).getTextContent());]