show loading before showing send result in jquery
you can do this by ajaxStart() and ajaxComplete()
$("#loading").ajaxStart(function(){ $(this).show(); });$("#loading").ajaxComplete(function(){ $(this).hide(); });or
$.ajax({ url : dle_root + 'engine/ajax/fast.php', data: { text: response, action: action }, beforeSend: function(){ $("#loading").show(); }, complete: function(){ $("#loading").hide(); }, success: function (data) { if (data == 'ok') { DLEalert(dle_p_send_ok, dle_info); } else { DLEalert(data, dle_info); } }); });
$('#button').click(function(){ $('#loading-div').html('<img src="..." />'); $.ajax({ type: 'POST', url: '...', data: {...}, success: function(response) { $('#loading-div').html(''); } });});In case if you have button with id="button", and some <div id="loading-div"></div> in which you can display image