Android:To set an item as selected when the ListView opens?

I post my solution, because google still doesn't know the answer.

getListView().setItemChecked(selectedGroupIndex, true);

In short, ListView::setSelection(int position) is what you need. However, depending on whether the device is in touch mode or not, it may or may not have visual effect (background highlighting). For more details, refer to Android ListView Selection Problem

If you use an Adapter for your ListView add this code to your adapter:

public class MyAdapter extends ArrayAdapter<MyClass> {    @Override    public View getView(int position, View convertView, ViewGroup parent) {        if (convertView == null) {            LayoutInflater inflator = (LayoutInflater) getContext()                    .getSystemService(Context.LAYOUT_INFLATER_SERVICE);            rowView = inflator.inflate(R.layout.my_adapter, null);        } else {            rowView = (View) convertView;        }        //...        // set selected item        LinearLayout ActiveItem = (LinearLayout) rowView;        if (position == selectedItem){            ActiveItem.setBackgroundResource(R.drawable.background_dark_blue);            // for focus on it            int top = (ActiveItem == null) ? 0 : ActiveItem.getTop();            ((ListView) parent).setSelectionFromTop(position, top);        }        else{            ActiveItem.setBackgroundResource(R.drawable.border02);        }        }    private int selectedItem;    public void setSelectedItem(int position) {        selectedItem = position;    }    }

In your Activity:

myAdapter.setSelectedItem(1);