Converting a string to an integer on Android
See the Integer class and the static parseInt() method:
http://developer.android.com/reference/java/lang/Integer.html
Integer.parseInt(et.getText().toString());You will need to catch NumberFormatException though in case of problems whilst parsing, so:
int myNum = 0;try { myNum = Integer.parseInt(et.getText().toString());} catch(NumberFormatException nfe) { System.out.println("Could not parse " + nfe);}
int in = Integer.valueOf(et.getText().toString());//orint in2 = new Integer(et.getText().toString());
Use regular expression:
String s="your1string2contain3with4number";int i=Integer.parseInt(s.replaceAll("[\\D]", ""));output:i=1234;
If you need first number combination then you should try below code:
String s="abc123xyz456";int i=NumberFormat.getInstance().parse(s).intValue();output:i=123;