How to extend android class which implements Parcelable interface? How to extend android class which implements Parcelable interface? android android

How to extend android class which implements Parcelable interface?


Parcelable, the Speed King

According to google engineers, this code will run significantly faster. One of the reasons for this is that we are being explicit about the serialization process instead of using reflection to infer it. It also stands to reason that the code has been heavily optimized for this purpose.

public abstract class BaseClass implements Parcelable {    public String FullName;    public boolean IsValidUser;    public String UserName;    public BaseClass () {    }    protected BaseClass(Parcel in) {        FullName = in.readString();        IsValidUser = in.readByte() != 0;        UserName = in.readString();    }    @Override    public void writeToParcel(Parcel dest, int flags) {        dest.writeString(FullName);        dest.writeByte((byte) (IsValidUser ? 1 : 0));        dest.writeString(UserName);    }}

Child class will be as follows with usage of list adding into parcelable object:

public class DerivedClass extends BaseClass {    public boolean IsSuccess;    public String Message;    public List<AnotherClass> AnotherClassObj;    public DerivedClass () {        super();    }    protected DerivedClass(Parcel in) {        super(in);        AnotherClassObj = new ArrayList<AnotherClass>();        IsSuccess = in.readByte() != 0;        Message = in.readString();        AnotherClassObj = in.readArrayList(AnotherClass.class.getClassLoader());    }    public static final Creator<DerivedClass> CREATOR = new Creator<DerivedClass>() {        @Override        public DerivedClass createFromParcel(Parcel in) {            return new DerivedClass(in);        }        @Override        public DerivedClass[] newArray(int size) {            return new DerivedClass[size];        }    };    @Override    public void writeToParcel(Parcel dest, int flags) {        super.writeToParcel(dest, flags);        dest.writeByte((byte) (IsSuccess ? 1 : 0));        dest.writeString(Message);        dest.writeList(AnotherClassObj);    }    public int describeContents() {        return 0;    }}

Another child class :

public class AnotherClass extends BaseClass {    public AnotherClass() {        super();    }    protected AnotherClass(Parcel in) {        super(in);    }    public int describeContents() {        return 0;    }    public static final Creator<AnotherClass> CREATOR = new Creator<AnotherClass>() {        @Override        public AnotherClass createFromParcel(Parcel in) {            return new AnotherClass(in);        }        @Override        public AnotherClass[] newArray(int size) {            return new AnotherClass[size];        }    };    @Override    public void writeToParcel(Parcel dest, int flags) {        super.writeToParcel(dest, flags);    }}

In Activity:

 Intent intent = new Intent(LoginActivity.this, MainActivity.class); intent.putExtra("UserObject", parcelableObject); startActivity(intent); finish();

In receiving activity:

Bundle extras = getIntent().getExtras(); if (extras != null) {      userObject = extras.getParcelable("UserObject"); }


Hi I've do research a lot about this, but I couldn't find useful anything. I try solution below and it worked for me.

Let say your super class has only int variable named "mData".

public class Location implements Parcelable { protected int mData; public int describeContents() {     return 0; } public void writeToParcel(Parcel out, int flags) {     out.writeInt(mData); } public static final Parcelable.Creator<Location> CREATOR         = new Parcelable.Creator<Location>() {     public Location createFromParcel(Parcel in) {         return new Location(in);     }     public Location[] newArray(int size) {         return new Location[size];     } }; private Location(Parcel in) {     mData = in.readInt(); }

}

Then, your extended class has only int variable named "mBattery".

public class LocationPlus extends Location { protected int mBattery; public int describeContents() {     return 0; } public void writeToParcel(Parcel out, int flags) {     out.writeInt(mBattery); } public static final Parcelable.Creator<LocationPlus> CREATOR         = new Parcelable.Creator<LocationPlus>() {     public LocationPlus createFromParcel(Parcel in) {         return new LocationPlus(in);     }     public LocationPlus[] newArray(int size) {         return new LocationPlus[size];     } }; private LocationPlus(Parcel in) {     mBattery = in.readInt(); }

}

So far, LocationPlus works fine. But we don't set variable of super class. Firstly, I set super class' variables on extended class with super(..) method. But it didn't work.

private LocationPlus(Parcel in) {     super(in);     mBattery = in.readInt(); }

Instead of code above, you should set all super class' variables explicitly. Super class' variables should be protected. Final constructor should be like this:

private LocationPlus(Parcel in) {     mData = in.readIn();     mBattery = in.readInt(); }

and writeToParcel method should be like this:

public void writeToParcel(Parcel out, int flags) {     out.writeIn(mData);     out.writeInt(mBattery); }


Try this solution:

public static final Parcelable.Creator<LocationPlus> CREATOR =    new Parcelable.Creator<LocationPlus>() {    @Override    public LocationPlus createFromParcel(Parcel in) {        Location l = Location.CREATOR.createFromParcel(in);        LocationPlus lp = new LocationPlus(l);        lp.mBattery= in.readInt();        return lp;    }    @Override    public LocationPlus[] newArray(int size) {        return new LocationPlus[size];    }};@Overridepublic void writeToParcel(Parcel parcel, int flags) {    super.writeToParcel(parcel, flags);    parcel.writeInt(mBattery);}