Random numbers in Java when working with Android Random numbers in Java when working with Android android android

Random numbers in Java when working with Android


java android integer

Docs are your friends

Random rand = new Random();int n = rand.nextInt(20); // Gives n such that 0 <= n < 20

Documentation:

Returns a pseudorandom, uniformly distributed int value between 0 (inclusive) and the specified value (exclusive), drawn from this random number generator's sequence. Thus, from this example, we'll have a number between 0 and 19

java android integer

Math.random() returns an double from [0,1[.Random.nextInt(int) returns an int from [0, int[.

java android integer

You can try:

int aNumber = (int) (20 * Math.random()) + 1;

or

Random rand = new Random();int n = rand.nextInt(20) + 1;

Recent Posts
How can I color dots in a xy scatterplot according to column value?
How to update a claim in ASP.NET Identity?
What does {0} mean when initializing an object?
Accessing members of items in a JSONArray with Java
How to log SQL statements in Spring Boot?
Powershell Get-WebSite name parameter is ignored
How to detect scroll to bottom of html element
Java synchronized method
How to test controllers with CodeIgniter?
Detect Visual Composer
Matplotlib: Specify format of floats for tick labels
Rails join a list of strings with commas and "and" before the last