Selecting a number from user with multiple numbers when using the contact picker

Alternatively, you can initially display the phone numbers associated with each contact in the Contact Picker and select one that way. Launch contact picker this way (note the different URI than my other answer):

Intent intent = new Intent(Intent.ACTION_PICK, ContactsContract.CommonDataKinds.Phone.CONTENT_URI);startActivityForResult(intent, REQUEST_PICK_CONTACT);

Then, in onActivityResult():

Uri result = data.getData();Log.v(TAG, "Got a result: " + result.toString());// get the phone number id from the UriString id = result.getLastPathSegment();// query the phone numbers for the selected phone number idCursor c = getContentResolver().query(    Phone.CONTENT_URI, null,    Phone._ID + "=?",    new String[]{id}, null);int phoneIdx = c.getColumnIndex(Phone.NUMBER);if(c.getCount() == 1) { // contact has a single phone number    // get the only phone number    if(c.moveToFirst()) {        phone = c.getString(phoneIdx);        Log.v(TAG, "Got phone number: " + phone);        loadContactInfo(phone); // do something with the phone number    } else {        Log.w(TAG, "No results");    }}

I was able to do this by creating a second dialog which shows all the phone numbers associated with a contact.First, call this somewhere in your code:

Intent intent = new Intent(Intent.ACTION_PICK, ContactsContract.Contacts.CONTENT_URI);startActivityForResult(intent, REQUEST_PICK_CONTACT);

Then in onActivityResult() use this to decide if the selected contact has multiple phone numbers, and display a dialog if so:

Uri result = data.getData();Log.v(TAG, "Got a result: " + result.toString());// get the contact id from the UriString id = result.getLastPathSegment();// query for phone numbers for the selected contact idc = getContentResolver().query(    Phone.CONTENT_URI, null,    Phone.CONTACT_ID + "=?",    new String[]{id}, null);int phoneIdx = c.getColumnIndex(Phone.NUMBER);int phoneType = c.getColumnIndex(Phone.TYPE);if(c.getCount() > 1) { // contact has multiple phone numbers    final CharSequence[] numbers = new CharSequence[c.getCount()];    int i=0;    if(c.moveToFirst()) {        while(!c.isAfterLast()) { // for each phone number, add it to the numbers array            String type = (String) Phone.getTypeLabel(this.getResources(), c.getInt(phoneType), ""); // insert a type string in front of the number            String number = type + ": " + c.getString(phoneIdx);            numbers[i++] = number;            c.moveToNext();        }        // build and show a simple dialog that allows the user to select a number        AlertDialog.Builder builder = new AlertDialog.Builder(this);        builder.setTitle(R.string.select_contact_phone_number_and_type);        builder.setItems(numbers, new DialogInterface.OnClickListener() {            @Override            public void onClick(DialogInterface dialog, int item) {                String number = (String) numbers[item];                int index = number.indexOf(":");                number = number.substring(index + 2);                loadContactInfo(number); // do something with the selected number            }        });        AlertDialog alert = builder.create();        alert.setOwnerActivity(this);        alert.show();    } else Log.w(TAG, "No results");} else if(c.getCount() == 1) {    // contact has a single phone number, so there's no need to display a second dialog}

I know this is an old question but I hope it helps.

Just in case someone stumbles across this again.

Another alternative to the other answers is the library https://github.com/codinguser/android_contact_picker

Full Disclosure: I am the author of this library