Wait for multiple promises to finish
You can use
removeAll() { Promise.all([ this.storage.remove(key1), this.storage.remove(key2), this.storage.remove(key3), ]).then(value => doSomething());See also https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/Promise/all
You could use Observable.forkJoin from rxjs by providing an array of all the observables/promises. This needs to be done before performing the operation. It's similar to Angular 1's $q.all.
rxjs version <= 6
Observable.forkJoin([ this.storage.remove(key1), this.storage.remove(key2), this.storage.remove(key3)]).subscribe(t=> { var firstResult = t[0]; var secondResult = t[1];});rxjs version > 6
import {forkJoin} from 'rxjs';forkJoin([ this.storage.remove(key1), this.storage.remove(key2), this.storage.remove(key3)]).subscribe(t=> { var firstResult = t[0]; var secondResult = t[1];});
On rxjs version > 6 You can do something like this:
import {forkJoin} from 'rxjs';and do instead of Observable.forkJoin this:
forkJoin([ this.service1.get(), this.service2.get()]).subscribe(data => { this.data1= data[0]; this.data2 = data[1];