What is the difference between the $parse, $interpolate and $compile services? What is the difference between the $parse, $interpolate and $compile services? angularjs angularjs

What is the difference between the $parse, $interpolate and $compile services?


Those are all examples of services that aid in AngularJS view rendering (although $parse and $interpolate could be used outside of this domain). To illustrate what is the role of each service let's take example of this piece of HTML:

var imgHtml = '<img ng-src="/path/{{name}}.{{extension}}">'

and values on the scope:

$scope.name = 'image';$scope.extension = 'jpg';

Given this markup here is what each service brings to the table:

  • $compile - it can take the whole markup and turn it into a linking function that, when executed against a certain scope will turn a piece of HTML text into dynamic, live DOM with all the directives (here: ng-src) reacting to model changes. One would invoke it as follows: $compile(imgHtml)($scope) and would get a DOM element with all the DOM event bounds as a result. $compile is making use of $interpolate (among other things) to do its job.
  • $interpolate knows how to process a string with embedded interpolation expressions, ex.: /path/{{name}}.{{extension}}. In other words it can take a string with interpolation expressions, a scope and turn it into the resulting text. One can think of the $interpolation service as a very simple, string-based template language. Given the above example one would use this service like: $interpolate("/path/{{name}}.{{extension}}")($scope) to get the path/image.jpg string as a result.
  • $parse is used by $interpolate to evaluate individual expressions (name, extension) against a scope. It can be used to both read and set values for a given expression. For example, to evaluate the name expression one would do: $parse('name')($scope) to get the "image" value. To set the value one would do: $parse('name').assign($scope, 'image2')

All those services are working together to provide a live UI in AngularJS. But they operate on different levels:

  • $parse is concerned with individual expressions only (name, extension). It is a read-write service.
  • $interpolate is read only and is concerned with strings containing multiple expressions (/path/{{name}}.{{extension}})
  • $compile is at the heart of AngularJS machinery and can turn HTML strings (with directives and interpolation expressions) into live DOM.


$interpolate-->Let us say you have two variables assigned to $scope object in the controller,$scope.a = 2;$scope.b = 3;var f = $interpolate("Result is : {{a*b}}");var result = f($scope);console.log(result);   --->'Result is 6'This means that $interpolate can take the string which has one or more angular expressions.Now $parse:var f1 = $parse("a*b");var result1 = f1($scope);console.log(result1);   ----> '6'**So $interpolate has the capability to evaluate a string with angular expressions mixed up in the string against the scope to get the result**.Another important difference between $interpolate and $parse,$eval is:**$interpolate has the capability to work with strings containing filters along with angular expressions.**This feature is not accessible in $eval , $parse.console.log($interpolate("Result is : {{a*b | currency : 'USD$'}}")($scope));---> 'Result is USD $6.00'

$interpolate does not have the write access to the $scope variables as we have in $eval and $parse

$parse , $interpolate --->needs to be injected but $eval need not be injected in the controller or where it is used

$parse , $interpolate give the function which can be evaluated against any context but $eval is always evaluated against $scope.

$eval and $interpolate behind the scenes uses $parse only.


Here is the cute explanation.

var img = img/{{name}}.{{extension}}$parse - > (name,extension) = > vimal , .jpg$interpolate -> use angular $parse and convert into string -> img/vimal.jpg$compile -> can turn html string img/vimal.jpg into live DOM so new img tag will be added inside our DOM with all prototype that a img tag have.