Apache rewrite subnet ip range

If you're using Apache HTTPD 2.4 or later, you can also use expressions to match REMOTE_ADDR against a CIDR mask directly, instead of converting these to regexps.

The short form looks like this:

RewriteCond expr "-R '192.168.1.0/24'"

The following longer form is also available, but the documentation suggests it is less efficient:

RewriteCond expr "%{REMOTE_ADDR} -ipmatch '192.168.1.0/24'"

Let's look at the first range:

54.192.0.0/16

In the regex

54\.192(\.(25[0-5]|2[0-4][0-9]||1[0-9]{2}|[1-9]?[0-9])){2} 

Notice the double ||. Given how hard it is to debug, if there is even one mistake, I don't feel bad throwing the whole thing away.

The following is not quite exact because it would match fragments up to 999, but all that matters is that it catches all IPs in the range, and no other valid IPs. It does.

54\.192\.[0-9]{1,3}\.[0-9]{1,3}

And it's easy to read. I would recommend using that instead. Try it, and if that works, the other ones can also be revisited.

I am not sure how you receive the IP, but depending on context this is another option:

RewriteCond %{REMOTE_ADDR} !^54\.192\.[0-9]{1,3}\.[0-9]{1,3}$

Let's look at some potential ranges:

54.192.0.0/16 => ^54\.192\.[0-9]{1,3}\.[0-9]{1,3}$54.230.0.0/16 => ^54\.230\.[0-9]{1,3}\.[0-9]{1,3}$54.239.128.0/18 => ^54\.239\.(?:19[01]|1[3-8][0-9]|12[89])\.[0-9]{1,3}$54.239.192.0/19 => ^54\.239\.(?:22[0-3]|2[01][0-9]|19[2-9])\.[0-9]{1,3}$54.240.128.0/18 => ^54\.240\.(?:19[01]|1[3-8][0-9]|12[89])\.[0-9]{1,3}$204.246.164.0/22 => ^204\.246\.16[4-7]\.[0-9]{1,3}$204.246.168.0/22 => ^204\.246\.(?:17[01]|16[89])\.[0-9]{1,3}$204.246.174.0/23  => ^204\.246\.17[45]\.[0-9]{1,3}$204.246.176.0/20 => ^204\.246\.(?:19[01]|18[0-9]|17[6-9])\.[0-9]{1,3}$205.251.192.0/19 => ^205\.251\.(?:22[0-3]|2[01][0-9]|19[2-9])\.[0-9]{1,3}$205.251.249.0/24 => ^205\.251\.249\.[0-9]{1,3}$205.251.250.0/23 => ^205\.251\.25[01]\.[0-9]{1,3}$205.251.252.0/23 => ^205\.251\.25[23]\.[0-9]{1,3}$205.251.254.0/24 =>  ^205\.251\.254\.[0-9]{1,3}$216.137.32.0/19 => ^216\.137\.(?:6[0-3]|[45][0-9]|3[2-9])\.[0-9]{1,3}$