Can std::array be used in a constexpr class?

Because std::array<T, N> is an aggregate, it can be initialized as a constexpr if and only if the underlying type T has a constexpr constructor (when presented with each initializer you provide).

Based on the comment by @MarkGlisse: this compiles

#include <array> #include <iostream>template<typename T, std::size_t N> struct X {    constexpr X(const std::array<T,N>& a):arr(a){}    private:    std::array<T,N> arr; }; constexpr std::array<int,2> a {{ 13, 18 }}; constexpr X<int,2> x = a;int main() {        }

I believe I have found the relevant quote from the Standard here:

12.1 Constructors [class.ctor]

6 A default constructor that is defaulted and not defined as deleted is implicitly defined when it is odrused (3.2) to create an object of its class type (1.8) or when it is explicitly defaulted after its first declaration. The implicitly-defined default constructor performs the set of initializations of the class that would be performed by a user-written default constructor for that class with no ctor-initializer (12.6.2) and an empty compound-statement. If that user-written default constructor would be ill-formed, the program is ill-formed. If that user-written default constructor would satisfy the requirements of a constexpr constructor (7.1.5), the implicitly-defined default constructor is constexpr.

This looks essentially like @BenVoigt's answer.