Check if a value exists in an array in Cython

You pretty much have to iterate through the array and check each element.

#include <stdbool.h>bool isvalueinarray(int val, int *arr, int size){    int i;    for (i=0; i < size; i++) {        if (arr[i] == val)            return true;    }    return false;}

Try next:

(read comments and tests for details how it working)

#include <stdio.h>#include <assert.h>/*Return index an integer number begin from start an array,otherwise return -1. */int indexOf(int *array, int array_size, int number) {    for (int i = 0; i < array_size; ++i) {        if (array[i] == number) {            return i;        }    }    return -1;}// Tests for indexOf()void test_indexOf() {    int array[10] = {12, 78, -43, 0, 21, 12, 20, -9, 1, -1};    assert(indexOf(array, 10, 12) == 0);    assert(indexOf(array, 10, 0) == 3);    assert(indexOf(array, 10, 2) == -1);    assert(indexOf(array, 10, 43) == -1);    assert(indexOf(array, 10, 11) == -1);    assert(indexOf(array, 10, -1) == 9);    assert(indexOf(array, 10, 1) == 8);    assert(indexOf(array, 10, -2) == -1);    assert(indexOf(array, 10, 3) == -1);}int main () {    test_indexOf();    return 0;}

Notes:

1. Since the C has not support for reload functions, indexOf() will be work only with array type of integer.

2. The C has not support for determinate length of a pointer of an array. So, you need manually pass size of array.

3. Testing environment:

-

$ uname -aLinux wlysenko-Aspire 3.13.0-37-generic #64-Ubuntu SMP Mon Sep 22 21:28:38 UTC 2014 x86_64 x86_64 x86_64 GNU/Linux$ gcc --versiongcc (Ubuntu 4.8.5-2ubuntu1~14.04.1) 4.8.5