Check if an awk array contains a value Check if an awk array contains a value arrays arrays

Check if an awk array contains a value


Awk noob here. I digested Steven's answer and ended up with this hopefully easier to understand snippet below. There are 2 more subtle problems:

  • An Awk array is actually a dictionary. It's not ["value1", "value2"], it's more like {0: "value1", 1: "value2"}.
  • in checks for keys, and there is no built-in way to check for values.

So you have to convert your array (which is actually a dictionary) to a dictionary with the values as keys.

BEGIN {    split("value1 value2", valuesAsValues)    # valuesAsValues = {0: "value1", 1: "value2"}    for (i in valuesAsValues) valuesAsKeys[valuesAsValues[i]] = ""    # valuesAsKeys = {"value1": "", "value2": ""}}# Now you can use `in`($1 in valuesAsKeys) {print}

For one-liners:

echo "A:B:C:D:E:F" | tr ':' '\n' | \awk 'BEGIN{ split("A D F", parts); for (i in parts) dict[parts[i]]=""}  $1 in dict'


what I do is structure my data to take advantage of what the language provides.

So instead of saying :

BEGIN {split("444 555 666", foo); .... }

say :

BEGIN { bar[ "444" ] ; ... }

or ala another suggestion:

BEGIN {   split("444 555 666", foo);  for( i in FOO ) bar[foo[i]];}

remember arrays in awk are really associative arrays.