Cleanest way to copy a constant size array in c++11
If you use std::array instead of a built-in array (which you should), it becomes very simple. Copying an array is then the same as copying any other object.
std::array<float,4> a = {0,1,2,3};std::array<float,4> b = a;
The C++03 way
Use std::copy():
float a[4] = {0,1,2,3};float b[4];std::copy(a,a + 4, b);That's about as clean as it gets.
The C++11 way
std::copy(std::begin(a), std::end(a), std::begin(b));If you can use std::array
With std::array you just do simple assignment:
std::array<float,4> a = {0,1,2,3};auto b = a;
For interested in C++03 (and also C) solution - always use struct containing an array instead of solely array:
struct s { float arr[5]; };Structs are copyable by default.
Its equivalent in C++11 is,already mentioned, std::array<float,5>;