Get the position of the largest value in a multi-dimensional NumPy array
The argmax() method should help.
Update
(After reading comment) I believe the argmax() method would work for multi dimensional arrays as well. The linked documentation gives an example of this:
>>> a = array([[10,50,30],[60,20,40]])>>> maxindex = a.argmax()>>> maxindex3Update 2
(Thanks to KennyTM's comment) You can use unravel_index(a.argmax(), a.shape) to get the index as a tuple:
>>> from numpy import unravel_index>>> unravel_index(a.argmax(), a.shape)(1, 0)
(edit) I was referring to an old answer which had been deleted. And the accepted answer came after mine. I agree that argmax is better than my answer.
Wouldn't it be more readable/intuitive to do like this?
numpy.nonzero(a.max() == a)(array([1]), array([0]))Or,
numpy.argwhere(a.max() == a)