How can I create an array in Kotlin like in Java by just providing a size?

java arrays arraylist kotlin

According to the reference, arrays are created in the following way:

For Java's primitive types there are distinct types IntArray, DoubleArray etc. which store unboxed values.
They are created with the corresponding constructors and factory functions:
```
val arrayOfZeros = IntArray(size) //equivalent in Java: new int[size]val numbersFromOne = IntArray(size) { it + 1 }val myInts = intArrayOf(1, 1, 2, 3, 5, 8, 13, 21)
```
The first one is simillar to that in Java, it just creates a primitive array filled with the default value, e.g. zero for Int, false for Boolean.
Non primitive-arrays are represented by Array<T> class, where T is the items type.
T can still be one of types primitive in Java (Int, Boolean,...), but the values inside will be boxed equivalently to Java's Integer, Double and so on.
Also, T can be both nullable and non-null like String and String?.
These are created in a similar way:
```
val nulls = arrayOfNulls<String>(size) //equivalent in Java: new String[size]val strings = Array(size) { "n = $it" } val myStrings = arrayOf("foo", "bar", "baz")val boxedInts = arrayOfNulls<Int>(size) //equivalent in Java: new Integer[size]val boxedZeros = Array(size) { 0 }
```

java arrays arraylist kotlin

Here is simple example of init of Array of String

        var names = Array<String>(<AnotherArray.size>) { i -> "" }

Kotlin doc

java arrays arraylist kotlin

In Kotlin, creating an IntArray of size N is simple. Use IntArray(n) or the appropriate type, as detailed thoroughly in hotkey's answer.

When utilizing your fixed size array, you can use Kotlin Destructuring

// Create fixed sized arrayval point = IntArray(2)// Access values directlyval (x, y) = point

In this case, x will be taken from index 0, y from index 1, etc.