How can I generate a list or array of sequential integers in Java?

With Java 8 it is so simple so it doesn't even need separate method anymore:

List<Integer> range = IntStream.rangeClosed(start, end)    .boxed().collect(Collectors.toList());

Well, this one liner might qualify (uses Guava Ranges)

ContiguousSet<Integer> integerList = ContiguousSet.create(Range.closedOpen(0, 10), DiscreteDomain.integers());System.out.println(integerList);

This doesn't create a List<Integer>, but ContiguousSet offers much the same functionality, in particular implementing Iterable<Integer> which allows foreach implementation in the same way as List<Integer>.

In older versions (somewhere before Guava 14) you could use this:

ImmutableList<Integer> integerList = Ranges.closedOpen(0, 10).asSet(DiscreteDomains.integers()).asList();System.out.println(integerList);

Both produce:

[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

The following one-liner Java 8 version will generate [ 1, 2 ,3 ... 10 ]. The first arg of iterate is the first nr in the sequence, and the first arg of limit is the last number.

List<Integer> numbers = Stream.iterate(1, n -> n + 1)                              .limit(10)                              .collect(Collectors.toList());