Initialize a constant sized array in an initializer list
While not available in C++03, C++11 introduces extended initializer lists. You can indeed do it if using a compiler compliant with the C++11 standard.
struct Test { Test() : set { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 } { }; int set[10];};
The above code compiles fine using g++ -std=c++0x -c test.cc
.
As pointed out below me by a helpful user in the comments, this code does not compile using Microsoft's VC++ compiler, cl. Perhaps someone can tell me if the equivalent using std::array
will?
#include <array>struct Test { Test() : set { { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 } } { }; std::array<int, 10> set;};
This also compiles fine using g++ -std=c++0x -c test.cc
.
Unfortunately, in C++03, you cannot initialize arrays in initializer lists. You can in C++11 though if your compiler is newer :)
see: How do I initialize a member array with an initializer_list?
"I understand that Set is just a pointer to the static array of 10 integers"
No, that's wrong: it's an array, not a pointer.
You can still initialize it in the constructor's initializer list.
For a compiler that doesn't support C++11 curly braces initialization (Visual C++ version 11 and earlier comes to mind) you'll have to jump through some hoops though, as shown below:
#include <iostream>#include <vector>using namespace std;#define CPP11#if defined( _MSC_VER )# if (_MSC_VER <= 1700)# undef CPP11# endif#endif#ifdef CPP11class Cpp11{private: int set_[10];public: Cpp11() : set_{ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 } {} int foo() const { return set_[3]; }};#endifclass Cpp03{private: struct IntArray10 { int values[10]; }; IntArray10 set_; static IntArray10 const& oneToTen() { static IntArray10 const values = { {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} }; return values; }public: Cpp03() : set_( oneToTen() ) {} int foo() const { return set_.values[3]; }};int main(){}
Instead of using raw arrays, though, use std::vector
and C+++11 std::array
, both of which are supported even by Visual C++ 11.