Java array substring

Use Arrays.copyOfRange:

public static <T> T[] copyOfRange(T[] original,                                  int from,                                  int to)

Copies the specified range of the specified array into a new array. The initial index of the range (from) must lie between zero and original.length, inclusive. The value at original[from] is placed into the initial element of the copy (unless from == original.length or from == to). Values from subsequent elements in the original array are placed into subsequent elements in the copy. The final index of the range (to), which must be greater than or equal to from, may be greater than original.length, in which case null is placed in all elements of the copy whose index is greater than or equal to original.length - from. The length of the returned array will be to - from.

The resulting array is of exactly the same class as the original array.

In your case:

String[] grp = Arrays.copyOfRange(elements, i, i + n);

You will use Arrays.copyOfRange().

Here is an example:

String[] original = some array;String[] grp = Arrays.copyOfRange(original, i, i + n);

The Javadocs for the Arrays class has lots of information about the method:

Use Arrays.copyOfRange():

String[] grp = Arrays.copyOfRange(grp, i, i+n);

As the name implies grp will be a copy of the original array and not a view into it. You can't have views into the array, for that you'd need to use a collection. Generally speaking collections are the more powerful and flexible, high-level alternative to arrays.