Lodash sort collection based on external array
var sortedCollection = _.sortBy(collection, function(item){ return firstArray.indexOf(item.guid)});
Here is just a simple add to the accepted answer in case you want to put the unmatched elements at the end of the sortedCollection and not at the beginning:
const last = collection.length;var sortedCollection = _.sortBy(collection, function(item) { return firstArray.indexOf(item.guid) !== -1? firstArray.indexOf(item.guid) : last;});
Input:
var data1 = ['129asg', '39342aa'];var data2 = [{ guid: '39342aa', name: 'John'}, { guid: '129asg', name: 'Mary'}];
First create an index object, with
_.reduce
, like thisvar indexObject = _.reduce(data2, function(result, currentObject) { result[currentObject.guid] = currentObject; return result;}, {});
And then
map
the items of the first array with the objects from theindexObject
, like thisconsole.log(_.map(data1, function(currentGUID) { return indexObject[currentGUID]}));
Output
[ { guid: '129asg', name: 'Mary' }, { guid: '39342aa', name: 'John' } ]
Note: This method will be very efficient if you want to sort so many objects, because it will reduce the linear look-up in the second array which would make the entire logic run in O(M * N) time complexity.