Parse JSON array file with JSONPATH

If the object is:

[  [50.4154134372953,-1.28486558931069,"CLASS B",9,205,0,"UK",431500382,3,4],  [50.3058858494047,-0.976070494820637,"CLASS B",9,239,0,"UK",2750350,21,2]]

Then "$[0]" will return:

[50.4154134372953,-1.28486558931069,"CLASS B",9,205,0,"UK",431500382,3,4]

And "$[1]" will return:

[50.3058858494047,-0.976070494820637,"CLASS B",9,239,0,"UK",2750350,21,2]

You can do it two levels deep as well. "$[0][4]" will return:

205

You can also extract the elements of the array into a list with "$[*]", which will return a list of 2 elements. The first being:

[50.4154134372953,-1.28486558931069,"CLASS B",9,205,0,"UK",431500382,3,4]

and the second being:

[50.3058858494047,-0.976070494820637,"CLASS B",9,239,0,"UK",2750350,21,2]

Using DefiantJS, you can search a JSON structure with XPath syntax. This library extends the global object JSON with a search function.

In this scenario, you can write something like this;

var data = [  [50.4154134372953,-1.28486558931069,"CLASS B",9,205,0,"UK",431500382,3,4],  [50.3058858494047,-0.976070494820637,"CLASS B",9,239,0,"UK",2750350,21,2]],search = JSON.search( data, '//*/*/*' );

Check out this fiddle; http://jsfiddle.net/hbi99/5NfeM/

This works for me

JsonPath.with(jsonResponse).param("name", "getName").get("findAll { a -> a.name == name  }")