Python 3 Building an array of bytes
Use a bytearray:
>>> frame = bytearray()>>> frame.append(0xA2)>>> frame.append(0x01)>>> frame.append(0x02)>>> frame.append(0x03)>>> frame.append(0x04)>>> framebytearray(b'\xa2\x01\x02\x03\x04')or, using your code but fixing the errors:
frame = b""frame += b'\xA2' frame += b'\x01' frame += b'\x02' frame += b'\x03'frame += b'\x04'
what about simply constructing your frame from a standard list ?
frame = bytes([0xA2,0x01,0x02,0x03,0x04])the bytes() constructor can build a byte frame from an iterable containing int values. an iterable is anything which implements the iterator protocol: an list, an iterator, an iterable object like what is returned by range()...