Result of 'sizeof' on array of structs in C? Result of 'sizeof' on array of structs in C? arrays arrays

Result of 'sizeof' on array of structs in C?


sizeof gives you the size in bytes, not the number of elements. As Alok says, to get the number of elements, divide the size in bytes of the array by the size in bytes of one element. The correct C idiom is:

sizeof a / sizeof a[0]


sizeof a / sizeof a[0];

This is a compile-time constant, so you can use it to, for example, create another array:

#define N sizeof a / sizeof a[0]int n_a[N];


sizeof returns the size in memory of the passed element. By dividing the size of an array by a single element size, you get the elements count.

Note that the element size may include some padding bytes as well. For this reason, a padded struct (e.g. when a char member is followed by a pointer) will have a sizeof value greater than it members size sum.

On the other hand, don't let it bother you when counting elements in an array: sizeof(a) / sizeof(a[0]) will still work as smooth as expected.