why does accessing an element in an array take constant time?

The array, effectively, is known by a memory location (a pointer). Accessing a[3] can be found in constant time, since it's just location_of_a+3*sizeof(int).

In C, you can see this directly. Remember, a[3] is the same as *(a+3) - which is a bit more clear in terms of what it's doing (dereferencing the pointer "3 items" over).

an array of 10 integer variables, with indices 0 through 9, may be stored as 10 words at memory addresses 2000, 2004, 2008, … 2036, so that the element with index i has the address 2000 + 4 × i. this process take one multiplication and one addition .since these two operation take constant time.so we can say the access can be perform in constant time

Just to be complete, "what structure is accessed in linear time?" A Linked List structure is accessed in linear time. To get the n element you have to travel through n-1 previous elements. You know, like a tape recorder or a VHS cassette, where to go to the end of the tape/VHS you had to wait a long time :-)

An array is more similar to an hard disk: every point is accessible in "constant" time :-)

This is the reason the RAM of a computer is called RAM: Random Access Memory. You can go to any location if you know its address without traversing all the memory before that location.

Some persons told me that HD access isn't really in constant time (where by access I mean "time to position the head and read one sector of the HD"). I have to say that I'm not sure of it. I have googled around and I haven't found anyone speaking of it. I DO know that the time isn't linear, because it is still accessed randomly. In the end, if you think that HD access isn't constant enough for you (but then, what is constant? the access of the RAM? considering Cache, Prefetching, Data Locality and Compiler optimizations?), feel free to consider the sentence as An array is more similar to an USB disk stick: every point is accessible in "constant" time :-)