Calling async method synchronously

You can access the Result property of the task, which will cause your thread to block until the result is available:

string code = GenerateCodeAsync().Result;

Note: In some cases, this might lead to a deadlock: Your call to Result blocks the main thread, thereby preventing the remainder of the async code to execute. You have the following options to make sure that this doesn't happen:

• Add .ConfigureAwait(false) to your library method or

• explicitly execute your async method in a thread pool thread and wait for it to finish:

    string code = Task.Run(() => GenerateCodeAsync).Result;

This does not mean that you should just mindlessly add .ConfigureAwait(false) after all your async calls! For a detailed analysis on why and when you should use .ConfigureAwait(false), see the following blog post:

• .NET Blog: ConfigureAwait FAQ

You should get the awaiter (GetAwaiter()) and end the wait for the completion of the asynchronous task (GetResult()).

string code = GenerateCodeAsync().GetAwaiter().GetResult();

You should be able to get this done using delegates, lambda expression

private void button2_Click(object sender, EventArgs e)    {        label1.Text = "waiting....";        Task<string> sCode = Task.Run(async () =>        {            string msg =await GenerateCodeAsync();            return msg;        });        label1.Text += sCode.Result;    }    private Task<string> GenerateCodeAsync()    {        return Task.Run<string>(() => GenerateCode());    }    private string GenerateCode()    {        Thread.Sleep(2000);        return "I m back" ;    }