Bash doesn't parse quotes when converting a string to arguments Bash doesn't parse quotes when converting a string to arguments bash bash

Bash doesn't parse quotes when converting a string to arguments


The reason this happens is because of the order in which the shell parses the command line: it parses (and removes) quotes and escapes, then replaces variable values. By the time $test gets replaced with One "This is two" Three, it's too late for the quotes to have their intended effect.

The simple (but dangerous) way to do this is by adding another level of parsing with eval:

$ test='One "This is two" Three'$ eval "set -- $test"$ echo "$2"This is two

(Note that the quotes in the echo command are not necessary, but are a good general practice.)

The reason I say this is dangerous is that it doesn't just go back and reparse for quoted strings, it goes back and reparses everything, maybe including things you didn't want interpreted like command substitutions. Suppose you had set

$ test='One `rm /some/important/file` Three'

...eval will actually run the rm command. So if you can't count on the contents of $test to be "safe", do not use this construct.

BTW, the right way to do this sort of thing is with an array:

$ test=(One "This is two" Three)$ set -- "${test[@]}"$ echo "$2"This is two

Unfortunately, this requires control of how the variable is created.


Now we have bash 4 where it's possible to do something like that:

#!/bin/bashfunction qs_parse() {     readarray -t "$1" < <( printf "%s" "$2"|xargs -n 1 printf "%s\n" ) }tab='   '  # tabulation hereqs_parse test "One 'This is two' Three -n 'foo${tab}bar'"printf "%s\n" "${test[0]}"printf "%s\n" "${test[1]}"printf "%s\n" "${test[2]}"printf "%s\n" "${test[3]}"printf "%s\n" "${test[4]}"

Outputs, as expected:

OneThis is twoThree-nfoo     bar  # tabulation saved

Actually, I am not sure but it's probably possible to do that in older bash like that:

function qs_parse() {    local i=0    while IFS='' read -r line || [[ -n "$line" ]]; do        parsed_str[i]="${line}"        let i++    done < <( printf "%s\n" "$1"|xargs -n 1 printf "%s\n" )}tab='   ' # tabulation hereqs_parse "One 'This is two' Three -n 'foo${tab}bar'"printf "%s\n" "${parsed_str[0]}"printf "%s\n" "${parsed_str[1]}"printf "%s\n" "${parsed_str[2]}"printf "%s\n" "${parsed_str[3]}"printf "%s\n" "${parsed_str[4]}"


The solution to this problem is to use xargs (eval free).
It retains double quoted strings together:

$ test='One "This is two" Three'$ IFS=$'\n' arr=( $(xargs -n1 <<<"$test") )$ printf '<%s>\n' "${arr[@]}"<One><This is two><Three>

Of course, you can set the positional arguments with that array:

$ set -- "${arr[@]}"$ echo "$2"This is two