build argument lists containing whitespace

There are (at least) two ways to do this:

Use an array and expand it using "${array[@]}":

bar() {    local i=0 args=()    for arg in "$@"    do        args[$i]="prefix $arg"        ((++i))    done    foo "${args[@]}"}

So, what have we learned? "${array[@]}" is to ${array[*]} what "$@" is to $*.

Or if you do not want to use arrays you need to use eval:

bar() {    local args=()    for arg in "$@"    do        args="$args \"prefix $arg\""    done    eval foo $args}

bash arguments whitespace

Here is a shorter version which does not require the use of a numeric index:

(example: building arguments to a find command)

dir=$1shiftfor f in "$@" ; do    args+=(-iname "*$f*")donefind "$dir" "${args[@]}"

bash arguments whitespace

Use arrays (one of the hidden features in Bash).

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