Can bash show a function's definition?
Use type
. If foobar
is e.g. defined in your ~/.profile
:
$ type foobarfoobar is a functionfoobar { echo "I'm foobar"}
This does find out what foobar
was, and if it was defined as a function it calls declare -f
as explained by pmohandras.
To print out just the body of the function (i.e. the code) use sed
:
type foobar | sed '1,3d;$d'