Check folder size in Bash

You can do:

du -hs your_directory

which will give you a brief output of the size of your target directory. Using a wildcard like * can select multiple directories.

If you want a full listing of sizes for all files and sub-directories inside your target, you can do:

du -h your_directory

Tips:

• Add the argument -c to see a Total line at the end. Example: du -hcs or du -hc.

• Remove the argument -h to see the sizes in exact KiB instead of human-readable MiB or GiB formats. Example: du -s or du -cs.

if you just want to see the folder size and not the sub-folders, you can use:

du -hs /path/to/directory

Update:

You should know that du shows the used disk space; and not the file size.

You can use --apparent-size if u want to see sum of actual file sizes.

--apparent-size      print  apparent  sizes,  rather  than  disk  usage; although the apparent size is usually smaller, it may be larger due to holes in ('sparse')      files, internal fragmentation, indirect blocks, and the like

And of course theres no need for -h (Human readable) option inside a script.

Instead You can use -b for easier comparison inside script.

But You should Note that -b applies --apparent-size by itself. And it might not be what you need.

-b, --bytes      equivalent to '--apparent-size --block-size=1'

so I think, you should use --block-size or -B

#!/bin/bashSIZE=$(du -B 1 /path/to/directory | cut -f 1 -d "   ")    # 2GB = 2147483648 bytes# 10GB = 10737418240 bytesif [[ $SIZE -gt 2147483648 && $SIZE -lt 10737418240 ]]; then    echo 'Condition returned True'fi

Use a summary (-s) and bytes (-b). You can cut the first field of the summary with cut. Putting it all together:

CHECK=$(du -sb /data/sflow_log | cut -f1)