Convert floating point variable to integer?
Assuming $myduration is a decimal or integer
$ myduration=6.5$ myduration=$( printf "%.0f" $myduration )$ echo $myduration6
It's not entirely clear, but I think you're asking how to convert a floating-point value (myduration) to an integer in bash. Something like this may help you, depending on which way you want to round your number.
#!/bin/bashfloor_val=ceil_val=function floor() { float_in=$1 floor_val=${float_in/.*}}function ceiling() { float_in=$1 ceil_val=${float_in/.*} ceil_val=$((ceil_val+1))}float_val=$1echo Passed in: $float_valfloor $float_valceiling $float_valecho Result of floor: $floor_valecho Result of ceiling: $ceil_valExample usage:
$ ./int.sh 12.345Passed in: 12.345Result of floor: 12Result of ceiling: 13